the Kantorovich solution seems to be exactly in the form x2/a and x3/a. but since the exact solution contains cosh(x2),cosh(x3) and cosh(a), do we normalize both solutions by putting g=k=a=1 and b= 1/5 and the plot with x3=[-1/5,1/5], x2=[-1,1]?
If you normalized your length parameter with respect to a as instructed by the problem, then to plot what you have been asked to plot, you should not need to refer to convenient choice like assue some arbitary numerical values to the parameters you mentioned.
Thanks! Initially, I missed the fact that lambda is (2n+1)Pi/2b and hence i was wondering how to normalize the cos terms. But since we get the length parameter from lambda it is easy
Kunal Samel @ on
Hello everyone
the Kantorovich solution seems to be exactly in the form x2/a and x3/a. but since the exact solution contains cosh(x2),cosh(x3) and cosh(a), do we normalize both solutions by putting g=k=a=1 and b= 1/5 and the plot with x3=[-1/5,1/5], x2=[-1,1]?
thanks
Kunal
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Kunal Samel @ on
i know this is not normalizing in the strict sense but for the sake of plotting
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Wenbin Yu @ on
If you normalized your length parameter with respect to a as instructed by the problem, then to plot what you have been asked to plot, you should not need to refer to convenient choice like assue some arbitary numerical values to the parameters you mentioned.
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Kunal Samel @ on
Thanks! Initially, I missed the fact that lambda is (2n+1)Pi/2b and hence i was wondering how to normalize the cos terms. But since we get the length parameter from lambda it is easy
thanks
Kunal
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